Running a file, with a relative filename

[Fredrik Lundh]

Nathan Clegg <nathan at islanddata.com> wrote:
> > sys.path.insert(0, "../yyy")
> > import prog2
> 
> I don't believe this will work unless you happen to be in the same
> directory as the toplevel script.

well, the question was if there was a way
to say:

    import "../yyy/prog2.py"'

which is exactly what my snippet does.  reading
Phil's post again, he might have meant "relative to
this module's location", in which case he could
add os.path.join(__file__, "../yyy") to the path
instead.

note that __file__ is only set for imported modules,
not for scripts.  for scripts, you have to use some-
thing like os.path.dirname(sys.argv[0])...

> A more bulletproof method would append
> 'yyy' in some way to the current sys.path[0]
> entry.

you mean sys.argv[0], don't you?  sys.path[0] tends
to be blank most of the time, at least on my boxes.

</F>