python + linux + cron = problem

[Jørn Eilertsen]

here's the whole script, well the part that gives me grief at least
:
#!/usr/bin/python
import commands

koblinger = commands.getoutput('df | grep eggum | cut -d 1 -f 1 | cut -d / -f
4')

I've tried to put the shell command into a shell script and run
commands.getoutput on the script but with the same result. Here's the cron
entry:
0 1 * * *   /usr/local/bin/sjekkmounts
and I've tried sh /usr/local/bin/sjekkmounts

Jorn

Doug Hellmann wrote:

> Jørn Eilertsen wrote:
> >
> > Hi,
> >
> > I've posted this earlier but noone replied so I'm trying again
> >
> > I have this small program which includes the following line og code:
> >  mounts = commands.getoutput('df | grep eggum | cut -d 1 -f 1 | cut -d /
> > -f 4')
> >
> > this runs fine from the commandline but when run as a cronjob I get the
> > following error:
> >
> > File "/usr/lib/python1.5/commands.py", line 42, in getoutput
> >     return getstatusoutput(cmd)[1]
> >   File "/usr/lib/python1.5/commands.py", line 53, in getstatusoutput
> >     sts = pipe.close()
> > IOError: (10, 'No child processes')
> >
> > The use of pipes seems to be the trouble here.
> >
> > Any help on how the get around this would be greatly appreciated.
> >
> >
>
> If the problem is really having pipes in the command, why not put your
> shell commands in a shell script, then run commands.getoutput() on that?
>
> If the program runs from the command line but not cron, the problem is
> more likely to be related to PATH problems within the cron environment.
> How do you set up the cron job?
>
> Doug