NameError when assigning dictionary values
Fredrik Lundh
effbot at telia.com
Sun Apr 2 19:44:23 EDT 2000
lewst <lewst at yahoo.com> wrote:
> I was trying to build a dictionary and create lists corresponding to
> the value names in the dictionary in one loop.
unlike Tcl, you don't need to create *variables* to be
able to store *values* to your dictionary.
> Do I really have to type "one" and "two" twice? Once to make it a
> variable and a second time to add to my dictionary? I.e,
no. reset your brain. forget about variables. just put
new *values* (aka objects) in the dictionary.
> This seems error prone if the the number of variables grows very large
> as it will for me.
let me guess: what you really want to do is to have a
number of lists, each of which are identified by a string?
mydict = {}
for k in ("one", "two"):
mydict[k] = []
and then you want to update one of them:
mydict["one"].append("1")
and then you want to print them all:
for k, v in mydict.items():
print k, v
did I successfully read your mind this time?
</F>
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