incrementation operators?

[Peter Schneider-Kamp]

Thomas Wouters wrote:
> 
> On Sun, Aug 13, 2000 at 08:42:08PM -0400, Colin J. Williams wrote:
> > 
> > Suppose one wishes to do a.append([5]).  It would appear that one would have to
> > return to the existing syntax.

You'll have to do:

a += [[5]]

> "a += 3" isn't equivalent to a.append(3), it's equivalent to
> 'a.extend(3)'. But you can write 'a.append(3)' as 'a.append([3])', and it's

                                                     ^^^^^^^^^^^^^
I am sure you meant:                                 a.extend([3])

> solved :-) You might have missed that in my original posting: I did say you
> could use augmented assignment in place of 'append' and 'extend', but my
> example had that extra pair of brackets you need to make it work.

Yes.

Peter
-- 
Peter Schneider-Kamp          ++47-7388-7331
Herman Krags veg 51-11        mailto:peter at schneider-kamp.de
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