a complement function

[Brad Knotwell]

Hello all--

I was wondering if there's a clean way to do the following:

def complement(function):
    return lambda x,function=function: not apply(function,x)

print complement(lambda x: x == 1)((1,))
print complement(lambda x: x == 1)((2,))
print complement(lambda x,y: x == y)((3,4))
print complement(lambda x,y: x == y)((4,4))


As you can see, it works fine as long as the function is called with
a tuple representing all arguments.  What I'd prefer is the more obvious
interface:

print complement(lambda x: x == 1)(1)
print complement(lambda x: x == 1)(2)
print complement(lambda x,y: x == y)(3,4)
print complement(lambda x,y: x == y)(4,4)

FWIW, I suppose the real question would ask if there's any way for
default arguments and variably-sized argument lists to play nicely
together.

TIA.

--Brad