Determine calling module's name

[Christian Tanzer]

David Goodger <dgoodger at bigfoot.com> wrote:

> on 2000-08-10 03:17, Roland Mas (mas at echo.fr) wrote:
> > (file, line, func, None) = list [len (list) - 3]
> ...
> > (file, func, None) = whocalled ()
> 
> Um. Assigning to None. Bad idea. Side effects. Ouch! Please be careful!

Don't get carried away:

-------------------------------------------------------------------------------
Python 1.5.2 (#5, Jan  4 2000, 11:37:02)  [GCC 2.7.2.1] on linux2
Copyright 1991-1995 Stichting Mathematisch Centrum, Amsterdam
>>> def not_foo () :
...     (f,g,None) = (1,2,3)
...     return f,g
... 
>>> print "%s" % None
None
>>> not_foo ()
(1, 2)
>>> print "%s" % None
None
>>> None==3
0
>>> None=3
>>> None==3
1
>>> print "%s" % None
3
>>> 
-------------------------------------------------------------------------------

The name `None' is bound in the scope of the assignment. No effect is
visible outside that scope.

-- 
Christian Tanzer                                         tanzer at swing.co.at
Glasauergasse 32                                       Tel: +43 1 876 62 36
A-1130 Vienna, Austria                                 Fax: +43 1 877 66 92