8 queen/game of life
Peter Immarco
android at micron.net
Wed Jun 14 23:34:44 EDT 2000
Prolog's excellent for this kind of problem too. (Sorry about the null-answer on
doing it in Python. :)
Peter.
Trent Mick wrote:
> On Thu, Jun 15, 2000 at 10:44:03AM +0800, root wrote:
> > newbie question.
> >
> > has anyone wrote the 8 non-attacking queen problem and conway's game of life
> > in python? i try but face a few newbie problems.
> >
> > 1. conway's game of life:
> > how to have a matrix in python?
> > the following is not good;
> >
> > r0=[0,0,0]
> > r1=[0,0,0]
> > ........
> >
> > m=[r0,r1,....]
> >
> > the matrix is fixed, which is not good. my solution use dictionary (i
> > know this is not the right way). the key is a tuple of the matrix
> > indices. the value is '0'. then base on game of life rule, update the
> > dictionary and print for next generation.
> >
> > m={}
> > m[(0,0)] = 0, m[(0,1)] = 1,....
>
> How about this:
>
> >>> m =[]
> >>> for i in range(5):
> ... m.append([])
> ... for j in range(5):
> ... m[i].append(i*j)
> ...
> >>> m
> [[0, 0, 0, 0, 0], [0, 1, 2, 3, 4], [0, 2, 4, 6, 8], [0, 3, 6, 9, 12], [0, 4,
> 8, 12, 16]]
> >>> m[0][0]
> 0
> >>> m[1][4]
> 4
> >>> m[2][4]
> 8
>
> However, if you are doing heavy linear algebra I believe you should check out
> NumPy.
>
> Trent
>
> --
> Trent Mick
> trentm at activestate.com
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