Andrew M. Kuchling
akuchlin at mems-exchange.org
Thu Mar 23 18:59:20 CET 2000
"Daley, MarkX" <markx.daley at intel.com> writes:
> result = crsr.fetchall()
What does fetchall() return when the result set is a single row? Try
printing repr(result) at each step. I'll wager that it returns a
single tuple, not a list of length 1 containing a tuple. This means
that the 'for item in range(len(result))' winds up looping over the
individual strings in the tuple. result[item] is therefore a string,
and 'data1, data2, data3, ... = result[item]' then unpacks the string
into single characters. This happens because strings are also
>>> a,b,c = 'abc'
>>> a,b,c = 'abcd'
Traceback (innermost last):
File "<stdin>", line 1, in ?
ValueError: unpack sequence of wrong size
If that's the case, you'd have to do something like this, to find when
.fetchall() hasn't returned a list, and turn it into a single-element
result = crsr.fetchall()
if type( result ) != types.ListType:
# Didn't return a list, so it must be a single tuple
result = [result]
for item in range(len(result)):
The author of the ODBC code shouldn't have written such an
inconsistent interface for fetchall(), though maybe there's some
esoteric reason for it.
A.M. Kuchling http://starship.python.net/crew/amk/
Nobody can be exactly like me. Sometimes even I have trouble doing it.
-- Tallulah Bankhead
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