Isn't re.findall supposed to find all?
junaftnoon at nospamplzyahoo.com
Sat Nov 11 00:31:57 CET 2000
Well, I forgot the old rule "Longest match possible."
It worked perfectly with this:
But another problem emerged. What if the brackets were
longer than one character? for example:
z='this is yet another start of a sting end but never start an end'
opening bracket : "start"
closing bracket : "end"
What I want to get is,
re.findall(p,z) == ['[start of a string end]','[start an end]']
How should I render the regular expression?
Thanks in advance
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