Filename in MultiFile

[Oleg Broytmann]

On Sun, 5 Nov 2000, Miki Tebeka wrote:
> I'm decoding mail with MultiFile and mimetools.
> How can I know the name of the current attachment I'm decoding?

m = mimetools.Message(mf) # mf is an instance of MyltiFile
name = m.getparam("name")
if not name:
   name = "outfile"

Oleg.
----
     Oleg Broytmann            http://phd.pp.ru/            phd at phd.pp.ru
           Programmers don't die, they just GOSUB without RETURN.