newbie - Regular expression help

[William Park]

On Sun, Nov 19, 2000 at 07:46:17AM -0500, Satheesh Babu wrote:
> Hi all,
> 
> I need to scan a string and replace all occurrences of
> "./" with null. But "../" shouldn't get changed.
> 
> Stupid way is to first replace ../ with AbRaCaDaBrA
> and then replace ./ with null and then replace
> AbRaCaDaBrA with ../
> 
> There should be a simpler solution.
> 
> Anyone, please...
> 
> Thx

Try
    re.sub('([^.])\./', r'\1', 'aa../bb./cc')
    re.sub('(?<!\.)\./', '', 'aa../bb./cc')

---William Park, Open Geometry Consulting