newbie - Regular expression help
June Kim
junaftnoon at nospamplzyahoo.com
Sun Nov 19 09:09:00 EST 2000
"Satheesh Babu" <vsbabu at erols.com> wrote in message
news:8v8i2a$lmt$1 at bob.news.rcn.net...
> Hi all,
>
> I need to scan a string and replace all occurrences of
> "./" with null. But "../" shouldn't get changed.
>
> Stupid way is to first replace ../ with AbRaCaDaBrA
> and then replace ./ with null and then replace
> AbRaCaDaBrA with ../
>
> There should be a simpler solution.
>
One simpler solution may be,
>>> pat=re.compile(r'[^.](\./)')
>>> pat.sub('',s)
> Anyone, please...
>
> Thx
>
>
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