if( result = function()) in Python - or reference arguments?
effbot at pythonware.com
effbot at pythonware.com
Fri Sep 8 07:24:06 EDT 2000
olav wrote:
> A beginners question:
>
> I have a function:
> def get_attr( _attrs, _key ):
> if _attrs.has_key( _key ):
> return _attrs[ _key ]
> else:
> return None
Note that you're emulating a standard dictionary
method here. Use _attrs.get(key) instead.
> That I would like to use about like this
> if ( attr = get_attr( attrs, 'title'))
> (this is C-syntax)
>
> Though its not accepted by the interpreter.
> Neither is the more Pythonlike:
> if attr = get_attr( attrs, 'title')
In Python, assignment is a statement, not an operator.
> How can I do this in Python?
Press the return key:
attr = attrs.get("title")
if attr:
...
</F>
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