md5.digest() -> readable form, like sha.hexdigest()

Oleg Broytmann phd at
Fri Sep 22 13:17:03 CEST 2000

On Fri, 22 Sep 2000, Thomas Weholt wrote:
> Ok, the subject says it all, but just in case:
> I need to store the output of the md5.digest()-method in a more human
> readable format, like the output from sha.hexdigest().
> How ??

   Attached is md5 wrapper module, that contains Guido's code to do exacly

     Oleg Broytmann              phd at
           Programmers don't die, they just GOSUB without RETURN.
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#! /usr/local/bin/python
   User wrapper for md5 builtin object

   Written by BroytMann, Jun 1997. Copyright (C) 1997 PhiloSoft Design

from md5 import md5

class md5wrapper:
   def __init__(self, init=None):
      if init:
         self._md5 = md5(init)
         self._md5 = md5()

   def update(self, data):

   def digest(self):
      return self._md5.digest()

   def __repr__(self):
      str = self.digest()
      return "%02x"*len(str) % tuple(map(ord, str))
         # This nice was suggested by Guido

   def md5file(self, f):
      if type(f) == type(''): # If f is string - use it as file's name
         infile = open(f, 'r')
         infile = f           # else assume it is opened file (fileobject) or
                              # "compatible" object (must has readline() method)

         while 1:
            buf =*1024)
            if not buf: break

         if type(f) == type(''): # If f was opened - close it

if __name__ == "__main__":
   print "This must print exactly the string"
   print "Test: 900150983cd24fb0d6963f7d28e17f72"
   print "Test:", md5wrapper("abc")

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