Separating IP nodes
scarblac-spamtrap at pino.selwerd.nl
Tue Sep 5 10:47:55 CEST 2000
Kevin Breit wrote in comp.lang.python:
> In my app, I have a user enter an IP address. Great. Now, I want to
> increment the last number. For example:
> 184.108.40.206 becomes 220.127.116.11 (yes...thats an odd IP)
> What is the best way to separate that and increment only the last number?
> I'm thinking some sort of regex, but not sure.
The best way to parse the IP address is to use socket.inet_aton(); it's
provided by the OS, should do all the necessary error checking
(255.255.255.255 is not a valid address, for example), and
accept all the ways to write an IP address.
But unfortunately that doesn't give an integer, but a four byte string.
Now if we're lazy and assume that unsigned integers are 32-bit, we can
use struct.unpack on it to get something like this:
import socket, struct
ip = struct.unpack('!I', socket.inet_aton(address))
ip = ip+1
return socket.inet_ntoa(struct.pack('!I', ip))
But if you're going to use this a long time you shouldn't be lazy and do
the unpacking by hand.
Remco Gerlich, scarblac at pino.selwerd.nl
Murphy's Rules, "Does Dr. McCoy know?":
FASA's Star Trek: The Role-Playing Game describes the Klingon Agonizer
as hand-held device 'applied to the left shoulder just above where the
ear is located in humans.'
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