Is there a more elegant way to do this?

Larry Whitley ldw at us.ibm.com
Thu Sep 14 11:31:39 EDT 2000


Thanks to all who have responded.  I will incorporate many of your
suggestions into the class method.

Larry


"Larry Whitley" <ldw at us.ibm.com> wrote in message
news:8poglt$10fq$1 at news.rchland.ibm.com...
> Here's the problem:
>
> I have a list of counters that will have a wide variety of different
values
> in them.  At intervals while the program runs, I will print out the
indexes
> of the counters with the five largest counts.  The counters are in a list
> identified below as self.counters.  Here's my inelegant way of doing it.
>
> def runningReport(self): # a method of a larger class
>     temp = [] # to make sure that temp is not just another reference to
> self.counters
>     temp = temp + self.counters # there are 100 individual counts in
> self.counters
>     temp.sort()
>     temp.reverse() # now largest value is first
>     temp2 = [] # for the result
>     for i in range( 5 ):
>         temp2.append( self.counters.index( temp[i] ) # find the index of
the
> next (largest) counter and store it in temp2
>     print temp2
>
> Surely there is a better way....
>
> Larry
>
>





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