How best to write this if-else?

[gzeljko]

From: Mick <vsl6 at paradise.net.nz>
> for i in all:
>     ma = i[0].match(str)
>     if ma:
>         i[1](ma)
> 

for r,f in all:
    ma = r.mach(str)
    if ma:
        f(ma)

ly-y'rs-gzeljko

> 
> Mick
> 
> 
> -----Original Message-----
> From: python-list-admin at python.org
> [mailto:python-list-admin at python.org]On Behalf Of Roy Smith
> Sent: Sunday, April 22, 2001 9:02 AM
> To: python-list at python.org
> Subject: Re: How best to write this if-else?
> 
> 
> "Ingo Wilken" <Ingo.Wilken at Informatik.Uni-Oldenburg.DE> wrote:
> > for e in [e1, e2, e3]:
> >     m = e.match(line)
> >     if m:
> >         text = m.group(1)
> >         break
> > else:
> >     no match found
> 
> OK, that's pretty neat, but I realize now that my example was
> unintentionally misleading.  The problem is not quite as regular as I made
> it out to be.
> 
> What if I want to execute different code depending on which expression I
> matched?  Something along the lines of (pseudocode):
> 
> if (m = e1.match(line)):
>    text1 = m.group(1)
>    do_complicated_processing (text1)
> elif (m = e2.match(line)):
>    text1 = m.group(1)
>    text2 = m.group(2)
>    print text1, text2
> elif (m = e3.match(line)):
>    return
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