Typo in Python Tutorial?

[Rupert Scammell]

In the Python Tutorial
(http://www.python.org/doc/current/tut/tut.html), Section 5.1, I
noticed that the pop() method for lists is documented as:

pop([i])
Remove the item at the given position in the list, and return it. If
no index is specified, a.pop() returns the last item in the list. The
item is also removed from the list.

I tried the following:

1.5.2 -
>>> mylist = ['one','two','three']
>>> list_item = mylist.pop([0])
Traceback (innermost last):
  File "<stdin>", line 1, in ?
TypeError: illegal argument type for built-in operation

2.0 -
>>> mylist = ['one','two','three']
>>> list_item = mylist.pop([0])
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
TypeError: an integer is required

However, in both versions, doing listitem = mylist.pop(0) works the
way I expect, making list_item == 'one', and mylist ==
['two','three'].

Section 5.1.2 in the Tutorial (Using Lists as Queues), however, uses
the mylist.pop(i) notation, which appears to be the correct way of
doing things.  Is something funny going on here, or is this a typo in
the documentation?

David Beazley's "Python Essential Reference", p. 22 mentions the
mylist.pop([i]) notation also.

--- Rupert

Rupert Scammell
rupe at metro.yak.net
http://metro.yak.net:8080