httplib slow read

[John Hunter]

>>>>> "Kjetil" == Kjetil Jacobsen <setattr at yahoo.no> writes:

    Kjetil> another option may be to use the pycurl module which wraps
    Kjetil> the curl library:

Thanks for the tip.  I have installed it and it looks nice.  One thing
I have not been able to figure out is how to direct pycurl to print
the HTTP header it would send were I too invoke 'perform'.  

Something like

import pycurl
c = pycurl.init()
c.setopt(pycurl.URL, 'http://www.python.org')
c.setopt(pycurl.REFERER, 'http://www.yahoo.com)

# tried this but it ain't right.
print pycurl.HTTPHEADER

How can I do this?

Aside from the internal __doc__ and the cURL pages and the
pycurl/tests files, is there any documentation I should be aware of?

Thanks,
John Hunter