index()-like behavior that returns all occurences...
Martin von Loewis
loewis at informatik.hu-berlin.de
Fri Dec 21 17:44:10 CET 2001
Lorin Hochstein <hawkestein at my-deja.com> writes:
> I've got a list of lists, something like this:
> x = [ , [1,2], , [1,2,3], , ,  ]
> I want to find the index of all of the empty lists.
> I know there's an index method of list, such that x.index() would
> return "2". But I want all of the indexes, not just the first one. Is
> there a simple way to do this (besides the obvious for-loop approach)?
List comprehension may be not that obvious
>>> [i for i in range(len(x)) if x[i] == ]
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