Why doesn't this work?
tim.one at home.com
Fri Dec 7 05:23:42 CET 2001
> Python 2.2b2 (#26, Nov 16 2001, 11:44:11) [MSC 32 bit (Intel)] on
> Type "copyright", "credits" or "license" for more information.
> IDLE 0.8 -- press F1 for help
> >>> def f(): return [1,2,3]
> >>> f()
> [1, 2, 3]
> >>> f().append(4)
> >>> l=f().append(4)
> >>> l
> Obviously I can fix this, but I'm wondering why it doesn't work
> the way I expected it to?
You didn't say what you expected, so how should we know <wink>?
list.append returns None. In general, most mutate-in-place methods of
mutable objects return None (list.append, list.remove, list.sort,
list.reverse, dict.update, ...). If they didn't, people would gripe about
x = [1, 2, 3]
y = x.append(4)
instead. "How come got 4 stuffed at the end of x too?"
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