boolean xor

[Delaney, Timothy]

Nope ... we're wanting a *logical* xor ...

def xor_wrong(a,b):
	return not(a==b)

def xor_right(a,b):
	return not((not a) == (not b))

print xor_wrong(0,1)
print xor_wrong(1,1)
print xor_wrong(2,1)

print xor_right(0,1)
print xor_right(1,1)
print xor_right(2,1)

Tim Delaney
Avaya Australia
+61 2 9352 9079

> -----Original Message-----
> From: ndev42 at yahoo.com [mailto:ndev42 at yahoo.com]
> Sent: Thursday, 11 January 2001 4:56 AM
> To: python-list at python.org
> Subject: Re: boolean xor
> 
> 
> 
> > I need a boolean (not bit-wise) xor function.  I've got the 
> following
> > function, but my logic skills are rusty enough that I'm wondering if
> > this is the "right" way to do it (I've validated that it 
> produces the
> > correct outputs, at least):
> >
> > def xor(a,b):
> >     return not ( (a and b) or (not (a or b)) )
> 
> A boolean xor is a detector of differences. Knowing that, you can
> simply write:
> 
> def xor(a,b):
> 	return not(a==b)
> 
> Hope it helps,
> --
> Nicolas
> 
> 
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