Language change and code breaks

[David Bolen]

Konrad Hinsen <hinsen at cnrs-orleans.fr> writes:

> Sounds like a good idea. Just the existence of two division operators
> would help newbies to recognize that there is a nontrivial problem.
> And a//b definitely beats (a+0.)/b, which does the trick, but is not
> at all evident.

Well, I'd probably suggest using "float(a)/b" instead which at least
makes it a little easier to see what's going on :-)

--
-- David
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