integer division rounding

Terry Reedy tjreedy at
Tue Jul 17 03:14:19 EDT 2001

> Why does an integer division resulting in a negative round down ,e.g -0.5
> => -1, while C and rounds up ,e.g -0.5 => 0. Is this a
> purposful error(?), or an oversight?

Purposeful.  This way, 0 <= m%n < n and (m/n)*n + m%n = m.
The other choice (round toward 0) maintains the invarient -(m/n) = (-m/n).
Much as we would like, we cannot make all three invarients true at once for
negative quotients.

Terry J. Reedy

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