Calling a user-defined Exception from within a function. Need Help.
jestes39 at yahoo.com
jestes39 at yahoo.com
Tue Jul 3 10:54:47 EDT 2001
I am still learning Python basics. I am trying to raise exceptions
within a function. The problem is that my named exceptions aren't
being recognized. They were working before I split the code up into
modules. I just need to know where I need to define the exceptions or
if I have to do something special to get them to work. Here's the
basic shell of the code:
import sys
import telnetlib
import dbi,odbc
import exceptions
class database_error(exceptions.Exception):
def __init__(self,args=NONE):
self.args = args
class other(exceptions.Exception):
def __init__(self,args=NONE):
self.args = args
def parse(record):
try:
#Parse the row into the variables that will be used to
# populate the receiving fields
.....
.....
return 'TRUE'
except:
return 'FALSE'
def receipt(record):
dbc = odbc.odbc(conn_str)
crsr = dbc.cursor()
try:
try:
if parse(record) == 'FALSE':
raise other
tn = cas_login.login(username,password,host)
try:
sql = "DELETE <table_name> WHERE ROWID = '" + rowid
+ "';"
crsr.execute(sql)
except:
raise database_error
except database_error:
dbc = None
crsr = None
tn.close()
print 'we made it to the database exception'
except other:
dbc = None
crsr = None
tn.close()
print 'unidentified error'
except:
dbc = None
crsr = None
tn.close()
print 'unhandled exception'
Any help or pointers would be greatly appreciated. Thanks.
Jason
More information about the Python-list
mailing list