'with' statement in python ?

[Emile van Sebille]

class test:
    def __init__(self, ln, wd):
        with self:
            ln = ln * 25.4 # keep in mm
            wd = wd * 25.4
            area = ln * wd

How could this be sorted out?

--

Emile van Sebille
emile at fenx.com

---------
"Carlos Ribeiro" <cribeiro at mail.inet.com.br> wrote in message
news:mailman.993562981.5640.python-list at python.org...
> At 11:49 26/06/01 +0000, Maciej Pilichowski wrote:
> >I have just started learning Python yesterday but...
> >
> > >def with_is_broken(a):
> > >   with a:
> > >     print x
> > >
> > >The snippet above assume that "a" must have a member attribute called
"x".
> >
> >Nope. As you referred to Pascal -- if "a" has a member "x" it is read
> >as "a.x", if not it is standalone "x".
>
> There must be some misunderstanding here. My snippet (incomplete, as I
> pointed out) assumed that Python had a "with" keyword, just to show the
> kind of problems that arise. In Python, the compiler/interpreter has no
way
> to tell beforehand if x is a member of a, a local variable, a module level
> variable, or a global variable. This ambiguity makes the use of with in
> Python impossible.
>
> Now, let us take a look at the "with" block in Pascal:
>
>    with a do
>      writeln(x);
>
> The compiler knows in advance everything about "a". If "a" does define a
> member called "x", then writeln() will reference "a.x". If "x" is not a
> member of "a", then the compiler will recursively search on the outer
> namespaces until it finds a definition for "x". If it does not find, it
> will stop - it is a fatal error, caught at compile time.
>
>
>
> Carlos Ribeiro
>
>
>