Getting all the *files* from a directory -- A better way??

[Fredrik Lundh]

Alex Martelli wrote:
> So wrap it up...:
>
> def joined_listdir(dir):
>     return [os.path.join(dir,f) for f in os.listdir(dir)]

or: glob.glob(os.path.join(dir, "*"))

> then use your wrapper:
>
> files1 = [f for f in joined_listdir(dir) if os.path.isfile(f)]

or: files1 = filter(os.path.isfile, joined_listdir(dir))

(shorter, faster -- and works for all versions of Python)

Cheers /F