string repr in 2.1

[Bernhard Herzog]

Robin Becker <robin at jessikat.fsnet.co.uk> writes:

> On related notes if repr no longer does octal escapes does string
> input still accept them?

Yes. Python wouldn't be backwards compatible otherwise.

> Also my trial of the 2.0 code versus an initial 2.1 coding reveals
> that an re based approach is very slow :( Anyone know simply what's
> involved in doing a codec?
> 
> My test code looks like
> 
> ######################################
> import sys, string
> from time import time
> _ESCAPELIST=256*[')']
> for c, n in {'\\':'\\\\', '(':'\\(',')':'\\)'}.items():
>      _ESCAPELIST[ord(c)]=n
> for c in range(0,32)+range(127,256):
>      n = '\\'
>      for i in (6,3,0):
>           n += "01234567"[(c>>i)&7]
>      _ESCAPELIST[c] = n

Why not simply

_ESCAPELIST[c] = '\\%03o' % c

?


Or for that matter, you could borrow some code from Sketch (taken from
Sketch/Lib/psmisc.py):

from string import join
import operator

def make_ps_quote_table():
    table = [''] * 256
    quote = (ord('('), ord(')'), ord('\\'))
    for i in range(128):
	if i in quote:
	    table[i] = '\\' + chr(i)
	else:
	    table[i] = chr(i)
    for i in range(128, 256):
	table[i] = '\\' + oct(i)[1:]
    return table

quote_table = make_ps_quote_table()

def quote_ps_string(text):
    return join(map(operator.getitem, [quote_table]*len(text), map(ord, text)),
                '')


   Bernhard

-- 
Intevation GmbH                                 http://intevation.de/
Sketch                                 http://sketch.sourceforge.net/
MapIt!                                               http://mapit.de/