Splitting on a regex w/o consuming delimiter

[Lars Kellogg-Stedman]

>> Given a string such as:
>>
>>   sample = 'one two @three @four five @six'
>>
>> I want to split it on the '@' character, but I want the '@'
>character to be
>> retained in each sequence.  That is, I'd like the above string split
>into:
>>
>>   one two
>>   @three
>>   @four five
>>   @six
>
>You could do '@'.split(sample)' (which deletes at) and then add back
>to all but first.

I knew I should have said it the first time:  this is a contrived example;
what if the delimiter regex was something like '\s(!|@)\s'?  Given:

  foo ! bar @ baz @ xyzzy ! mumble

You'd end up with:

 [ 'foo', 'bar', 'baz', 'xyzzy', 'mumble' ]

With no way of recovering the delimeter.

Really, I just want to be able to split on (?=pattern), or some other
method of splitting a string without consuming the delimiter.

-- Lars

-- 
Lars Kellogg-Stedman <lars at larsshack.org> --> http://www.larsshack.org/