how to express the following regular expression?
tim at vegeta.ath.cx
Wed Nov 21 11:36:09 CET 2001
Stephen <fungho at sinaman.com> graced us by uttering:
> I want to search the following formats:
So... this will match all of the following:
'1234R', '123R', '12R', '1R', 'R'
Is this what your want? (ie, 0 or more digits followed by an 'R'?)
Or did you mean '+' instead of '*'?
'P1234', 'P123', 'P12', 'P1', 'P'
> this means there must be a 'P' before the number or a 'R' after the
> number. However, I think I can't use this:
> because the number without P and R is also matched!
Yes, this is also a bad choice, as this matches, well, nothing. Since
the above regex doesn't require that *anything* is present in the
string, it tests true for the following:
'1234', 'P1234', '1234R', 'P1234R', 'PR',
'P', 'R', '', 'arbitrary string'
> How can I express it?
You need to know exactly what you want the regex to match before you can
write a well-crafted regex. Assuming you want one of the two following:
- the character 'P', followed by 1 or more digits ([0-9])
- 1 or more digits ([0-9]) followed by the character 'R'
...you can use the following:
my_regex = re.compile(r'(P\d+|\d+R)')
A diplomat is man who always remembers a woman's birthday but never her age.
-- Robert Frost
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