__getatr__ question

[Jim]

The following code is used to create a class.  If I make an instance
of the class called "k", then calling k.func1(23) will print
"k.func1(23)", and calling k.func2() will print "k.func2()" and return
12.  The problem occurs when I nest the functions like this:
k.func1(k.func2()).  This prints "k.func2()", "k.func2(12)" when I
really want it to print "k.func2()", "k.func1(12)".  It gets more
interesting when I do something like k.func1(k.func2() + k.func3()). 
This results in a printout of "k.func2()", "k.func3()", "k.func2(12)".

What's up with this, and it a bug or a feature of python?  It seams
like the __getattr__ is not being called/refreshed in the external
function if it is also called inside the function.

Thanks for any help

-Jim

****** Code *******

class klass:

    def __init__(self, name):
        self.name = name

    def __getattr__(self, a):

        self.string = a
        return(self.nop)

    def __repr__(self):
        return ''

    def nop(self, a = None):

        if (a == None):
            #pass
            print self.name + '.' + self.string + '()'
            return 12
        
        else:
            #pass
            print self.name + '.' + self.string + '(' + str(a) + ')'