a better prime number generator
Emile van Sebille
emile at fenx.com
Sun Oct 21 20:47:22 CEST 2001
Hi Rupendra,
Without commenting on speed of your algorithm, you may want to compare to
the primes.py distributed in the demo/scripts directory of the cvs version:
---------primes.py--------
#! /usr/bin/env python
# Print prime numbers in a given range
def main():
import sys
min, max = 2, 0x7fffffff
if sys.argv[1:]:
min = int(eval(sys.argv[1]))
if sys.argv[2:]:
max = int(eval(sys.argv[2]))
primes(min, max)
def primes(min, max):
if 2 >= min: print 2
primes = [2]
i = 3
while i <= max:
for p in primes:
if i%p == 0 or p*p > i: break
if i%p <> 0:
primes.append(i)
if i >= min: print i
i = i+2
main()
--------------------
Another note: you should use spaces for indentation when posting. Some
readers (mine included) lose the tabs which forces anyone looking at the
code to re-indent, sometimes introducing other bugs. Bottom line is that
more people will look closer at your code fragments if they look like they
can be run.
HTH,
--
Emile van Sebille
emile at fenx.com
---------
"Rupendra Dhillon" <dhillon_rs at rediffmail.com> wrote in message
news:23d58b26.0110210939.55bb7e0c at posting.google.com...
> hi all,
> I have just been introduced to pyton and find it a very good ( takes
> off all the bookwork ) language. I was trying to develope a ast prime
> number generator. I designed the following algo. Can you please
> suggest a faster one or modifications to this only to make it faster
>
> #the following algo returns all the primes below x
>
> def getPrimesTill(x):
> a = range(2,x)
> c = [2]
>
> i = 0
> j = 0
>
> foundone = 1
>
> while i < len(a):
> while j < len(c) and (c[j] < (.5 * a[i]) ) and foundone == 1:
> if a[i]%c[j] == 0:
> foundone = 0
> j = j + 1
> if foundone == 1 and i > 0:
> c.append(a[i])
> j = 0
> foundone = 1
> i = i + 1
> return c
>
>
> roop
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