Conditional operator in Python?
thp at cs.ucr.edu
thp at cs.ucr.edu
Tue Sep 4 02:07:49 EDT 2001
Terry Reedy <tjreedy at home.com> wrote:
: <thp at cs.ucr.edu> wrote in message news:9n1hr7$7op$1 at glue.ucr.edu...
:> Marcin 'Qrczak' Kowalczyk <qrczak at knm.org.pl> wrote:
:> : Sat, 31 Mar 2001 21:22:54 -0800, Erik Max Francis
: <max at alcyone.com> pisze:
:>
:> :> The Python FAQ, for instance, suggests x ? a : b can be reliably
:> :> substituted with
:> :>
:> :> (x and [a] or [b])[0]
: If you *know* that a will always evaluate as <true>, then 'x and a or
: b' works fine. All the rigamarole of tuples or lambdas is only needed
: to protect against the possibility of a evaulating as false. When it
: is not possible, said protection is not necessary.
:> Agreed. Something more aesthetic is definitely needed. I hate
: writing:
:>
:> factorial = lambda x : (x<=1 and [1] or [x*factorial(x-1)])[0]
: Since 1 != 0, quite dependably, you do not need to. try "x<=1 and 1 or
: x*factorial(x-1)"
Agreed. That helps in this particular case, but:
- Correctness depends on the second operand being nonzero, which
is not determinable in the general case.
- It's still less aesthetic than the common ?: syntax.
- It's still a hack (but a less ugly one).
A more elegant syntax is badly needed.
Tom Payne
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