filter with dynamic value

[Mikael Olofsson]

On 14-Sep-2001 Achim Domma wrote:
 >  I have something like this:
 >  
 >  ids = [(1,'abc'),(2,'abc'),(3,'xyz'),(4,'xyz')]
 >  comp = 'xyz'
 >  
 >  now I want to use filter to remove all items from ids which don't have
 >  'xyz'
 >  as second value. I think the following should work:
 >  
 >  filter(lambda x: x[1]=='xyz')
 >  
 >  but how can I do this with an dynamic value ? If I try the following I get
 >  problems with the scope of comp :
 >  
 >  filter(lamdba x: x[1]==comp)
 >  
 >  I think this can't be to complicated, but it seems that my C++ trained
 >  brain hides once again the solution from me ...

First of all, you need to provide the original list ids. Try the following.

  filter(lambda x: x[1]=='xyz', ids)

Second, you misspelled lambda in your second filter. If comp is global,
you can do the following

  filter(lambda x: x[1]==comp, ids)

But if comp is local, the following should do:

  filter(lambda x, comp=comp: x[1]==comp, ids)

HTH
/Mikael

-----------------------------------------------------------------------
E-Mail:  Mikael Olofsson <mikael at isy.liu.se>
WWW:     http://www.dtr.isy.liu.se/dtr/staff/mikael               
Phone:   +46 - (0)13 - 28 1343
Telefax: +46 - (0)13 - 28 1339
Date:    14-Sep-2001
Time:    15:29:28

         /"\
         \ /     ASCII Ribbon Campaign
          X      Against HTML Mail
         / \

This message was sent by XF-Mail.
-----------------------------------------------------------------------
Linköpings kammarkör: www.kammarkoren.com