smtp.sendmail read receipt?
Scott Nadeau
scott.nadeau at sanmina.com
Mon Sep 10 16:01:43 EDT 2001
I'm trying to figure out how to get a read receipt when a recipient
has read an e-mail that my program is sending. I've searched the web
for the answer, but I can't seem to find it. This is my current
(working) code...
filename = os.path.join('/opt', 'BravoFive', 'fet', 'mailer')
def contents():
if os.path.isfile(filename):
fd=open(filename, 'r')
a = fd.read()
os.remove(filename)
return a
else:
pass
try:
contentslist = string.split(contents())
custname=contentslist[1]
partnum=contentslist[4]
except:
pass
if os.path.isfile(filename):
try:
import smtplib
s = smtplib.SMTP("eagle-r")
s.sendmail ("me at here.com",tolist, "Subject: " + " " + custname +
" " + partnum + " Ready to Release\n\n%s" % contents())
s.quit()
except:
print('Error: releaseMailer.py')
else:
pass
any ideas?
Thanks!
Scott Nadeau
Concord, NH
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