Faster md5/1-way encryption?

[Alexander Skwar]

»Mike C. Fletcher« sagte am 2002-04-24 um 18:28:11 -0400 :
> Something that hits me right off the bat:
> 
> >             md5_zeile = md5.new(zeile).hexdigest()
> >             self_Inhalt += md5_zeile + linesep
> 
> Would likely be much better as:
> 
> 	myResults = []
> 	...
> 	myResults.append( md5.new(zeile).hexdigest() )
> 	...
> 	myResults = string.join( myResults, os.linesep )

Yes, that makes sense.  Thanks!

> Which would save you creating and destroying huge numbers of (at the end 
> of processing) very large strings.  If you can avoid that last step 

Yes, I also noticed, that it gets slower and slower over the time.

> can replace your 'i' counter in that approach (won't be a noticable 
> savings, I just hate counters :) ).

Sure, nice idea.

> accurate result as to current position.  Unless you really need that 
> accuracy, consider just accumulating the length of the lines you're 
> processing and adding 1 or 2 each time for the length of os.linesep.

Yes, of course.  Good idea here as well.

> MD5 can process gigabytes of information pretty quickly, so I'd be 
> surprised if a 100,000 line file is a huge problem.

Yes, that's right, but in the case of processing gigabytes of data,
you're just invoking the digest generation once and not over and over
again; and you're also creating the object once and not 100,000 times.

Thanks for your hints!

Alexander Skwar
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