file_ref = open(string_ref)

[Fernando Pérez]

Greg Weeks wrote:

> Is this code
> 
> C1:        file_ref = open(string_ref)
> 
> better than this?:
> 
> C2:        file = open(string)
> 

Definitely, but not for the reasons you state ;) Rather b/c with C2 you've 
just obliterated the new file builtin (synonym to open) and the string module 
name. So regardless of the IMHO needless distinction (in python, 'everything 
is a name which points to an object') between objects and references, I'd use 
C1 or something that doesn't use names of standard things like 'file' or 
'string' for my own variables.

Cheers,

f.