looping through a list

[Emile van Sebille]

Hugh writes:
> result = c.fetchone()

Try this in the interpreter.  I'd expect (but don't know for sure) that
you're getting a list back...

>   if (result != ""):

If so, you'll always pass through this...

... and if you're getting a string you could be saying ' if result:'

>     i=0
>     text = '<tr width = "80%" align = "center">'

you may want to be using a list here instead of a string.  appending to
lists is more efficient than concatenating strings.

>     while (i != len(result)+1):

this could be ' for returneditem in result:'    assuming a list result.

>       i = i + 1
>       text = text + '<td align = "center" valign =
> "top">'+str(result[int(i)])  +'</td>'

you certainly don't need int() here.

>     text = text + "</tr>"

this probably wants to be
text.append('''<td align = "center" valign ="top">%s</td></tr>''' %
returneditem)

>     page.generate("","",sessionID,text)
>   else:
>     text = '<h4>No items found</h4>'
>     page.generate("","",sessionID,text)
>
>
> At the moment, it keeps saying list index out of bounds and I don't
> know where I'm going wrong. I've tried all sorts of things in the
> While statement and still can't get it going.


You're probably going wrong by adding 1 in testing

while (i != len(result)+1):

as i subsequently indexes into result.  In python, indexes end one shy
of the length.

HTH,


--

Emile van Sebille
emile at fenx.com

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