Sorting a list to by another's order

[Graeme Longman]

Hi,

I have two lists:

listA = ['d', 'c', 'f', 'a', 'b', 'e']
listB = ['a', 'c', 'd', 'f']

I need to sort listA so that it's order corresponds to that of listB (if
the item in listA isn't in listB then it should be at the end of the
list)

Is there a quick way to do this using sort() instead of writng a bunch
of for loops and if-else statements ?

Thanks very much.
Graeme