is list always with reference ?
pyth at devel.trillke.net
Tue Aug 27 15:09:09 CEST 2002
Nikola Plejic wrote:
> Actually, not all of them...
> If you do this:
> >>> list1 = ["my", "sample", "list"]
> >>> list2 = list1
> >>> list2
> ['my', 'sample', 'list']
> >>> list2 = list1 * 2
If you keep in mind that 'list1' and 'list2' are
names which are bound to an object
things get easier to understand. And note, that
the '=' is used to express the (re)binding operation.
'list1*2' returns a new list object
'list2 = ...' binds the righthandside object to the name 'list2'
is *not* a rebinding operation. it modifies the list object
*in-place* and thus has no affect on any name bindings.
hope this de-construction helps,
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