Checking strings for "bad" characters
hst at empolis.co.uk
Wed Aug 28 10:41:31 CEST 2002
Peter Hansen wrote:
> Harvey Thomas wrote:
> > I've got some very long Unicode strings which I wish to
> test for the presence of ASCII characters 0-8 and 14-31. My
> first thought was to use regular expressions, e.g.:
> > import re
> > r = re.compile(u'[%s%s]' % (''.join([unichr(x) for x in
> range(0, 9)]) , ''.join([unichr(x) for x in range(14, 32)])))
> > amatch = r.search(r)
> > if amatch:
> > print "Bad characters"
> > else:
> > print "OK"
> > but is there a better or faster method.
> If you could use string.maketrans and .translate() to convert
> all bad characters
> that might be present into a single code (e.g. \x00), and
> then do a simple
> .find() for that character, you might get the benefits of
> simplicity and extreme
Thanks for the suggestion Peter, but it's much slower than the RE. I guess it's because of the creation of a new string which is then scanned. I suppose the only thing faster than the RE is a C extension, but I don't think the effort needed for that is worthwhile.
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