function calls ...
brueckd at tbye.com
brueckd at tbye.com
Tue Aug 20 15:57:30 EDT 2002
On Tue, 20 Aug 2002, Axel Bock wrote:
> Now I have a special problem: I have a dictionary, and I have a function.
> And I want to call the function with the dictionary as parameter, but I
> want a *COPY* of the dictionary be transferred, cause the function makes
> changes to this one which I don't like to keep but are nonetheless
> neccessary.
>
> With lists it works like this:
> callme(list[:])
> but with dictionaries ... ?
Well, do you want a copy of the dictionary or a copy of the dictionary and
a copy of all of its members too? To get the same behavior as above with
the list, use the dictionary's copy member:
>>> a = {'foo':5}
>>> b = a.copy()
If you want copies of everything use the copy module's deepcopy function.
-Dave
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