What is the most efficient way to do this?

Benji York benji_york at cal-na.com
Fri Feb 8 17:18:02 EST 2002

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How about:

>>> l = ['', '1', '2', '3', '', '456', '789', 'wow']
>>> filter(None, l)
['1', '2', '3', '456', '789', 'wow']

--
Benji York
york6 at mindspring.com

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