Question on if, while, for.... Figured it out..
phr-n2002a at nightsong.com
Mon Feb 11 23:42:23 CET 2002
c at tech.usd253.org (Fred) writes:
> if num > den: #Test for improper fraction.
> i = num/den #This will only return the whole part.
> j = num%den #This will return only the remainder.
> if j != 0:
> for i in range(9,0,-1):
> if num%i == 0 and den%i ==0 and test != 1:
> a = j/i
> b = den/i
> print "You entered an improper fraction, simplified it
> is: %d %d/%d" % (i,a,b),
> test = 1
Does this do what you really want, if the fraction entered is 8/12?
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