importing a sibling module

[Chris Liechti]

"Clark C . Evans" <cce at clarkevans.com> wrote in 
news:mailman.1010160546.8297.python-list at python.org:
> On Fri, Jan 04, 2002 at 11:14:58AM +0100, Alex Martelli wrote:
>| >     folder    files
>| > /zz/V13/lib  tool.py
>| > /zz/V13/app  prog.py
>| > /zz/V14/lib  tool.py
>| > /zz/V14/app  prog.py
>| ...
>| > What I'd like to do, within prog.py is "import ../lib/tool.py"
> ... 
>| import os, sys, imp
>| app_dir, appfilename = os.path.split(sys.argv[0])
>| lib_dir = os.path.join(app_dir,'../lib')
>| imp.load_module('tool', *imp.find_module('tool',[libdir]))
> 
> Thank you Alex; unfortunately, this returns an app_dir of '' 

try os.path.abspath() to get a canonical path...

> Is there any way to ask a module for it's pathname?  Say
> __mypath__ returns this.  Then I could pop "app" from the
> path, push "lib" on the path and then import tool.py using
> the technique you described.
> 
> Best,
> 
> Clark

-- 
Chris <cliechti at gmx.net>