efficient mega-replacements

[Kragen Sitaker]

Jonathan Hogg <jonathan at onegoodidea.com> writes:
> In case you hadn't realised it I thought I'd note that using "regexp"
> strings will save a lot of the stramash of backslashes in your code, as
> follows:
> 
>             val = val.replace("'","''")\
>                      .replace(r"\",r"\\\\\\\\")\

You didn't actually try this, did you?  :)

> The r'' form of string literals doesn't interpret backslashes.

Approximately true.