tomorrow in yyyymmdd format

[Gerhard Häring]

Giulio Cespuglio wrote in comp.lang.python:
> Hello everybody,
> 
> We all know that if I want to get the present GMT date in yyyymmdd
> format I should say
> 
> 	print time.strftime("%Y%m%d", time.gmtime() )
> 
> Now, what about tomorrow? Note that a simple string manipulation is
> not the solution I'm looking for, as tomorrow might be next month,
> next year, the 29th of February and such.
> Do you confirm that there's nothing better than the following
> silly-looking expression?
> 
> 	time.strftime("%Y%m%d", time.gmtime(time.time() + 60*60*24))

No, there's nothing better. Unless you're using the DateTime type from
the eGenix mxExtensions:

>>> import mx.DateTime as DateTime
>>> DateTime.today()
<DateTime object for '2002-06-19 00:00:00.00' at 81274e0>
>>> print DateTime.today()
2002-06-19 00:00:00.00
>>> print DateTime.today() + 1
2002-06-20 00:00:00.00
>>> 

Gerhard
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reduce(lambda x,y:x+y,map(lambda x:chr(ord(x)^42),tuple('zS^BED\nX_FOY\x0b')))