Operator overload question

[Arthur Siegel]

Given:

class Complex(complex):
    def __mul__(self,other):
       other=Complex(other)
       t = complex.__mul__(self,other)
       return Complex(t.real,t.imag)
    __rmul__ = __mul__

    def __add__(self,other):
       other=Complex(other)
       return
Complex(self.real.__add__(other.real),self.imag.__add__(other.imag))
    __radd__ = __add__

Then:

print type(Complex(5,4) * 7)
>><class '__main__.Complex'>
print type(7 * Complex(5,4))
>><class '__main__.Complex'>
print type(Complex(5,4) + 7)
>><class '__main__.Complex'>

But:

print type(7 + Complex(5,4))
>><type 'complex'>

Multiple choice:
  That the result at But is a surprise to me because I am missing:
      1)Something obvious about __radd__ or general classic syntax
      2)Something related to new style classes
      3)Other

Art