Exceptions and modules / namespaces question

[Cliff Wells]

On 28 Mar 2002 15:21:24 -0800
Preston Landers wrote:

> The problem, in a nutshell, is that I can't seem to catch an exception
> in the same module it was defined in if the function that raised the
> exception is in a different module, because of naming issues.
> 
> -------module2.py:
> 
> import module1
> 
> def raise_foo_exception():
>    raise module1.FooException("HELLO")
> 
> -------module1.py:
> 
> import exceptions, sys
> 
> class FooException(exceptions.Exception):
>    pass
> 
> def main():
> 
>    try:
>        import module2
>        module2.raise_foo_exception()
>    except FooException, e:
>        print "Got it!"
>    except:
>        xi = sys.exc_info()
>        print "Didn't get it.  Got this instead:", xi[0], xi[1]
> 
> if __name__ == "__main__":
>    main()
> 
> ---------result:
> 
> Didn't get it.  Got this instead: module1.FooException HELLO
> 
> 
> 
> The question is, how do I explicitly catch FooException in main()
> without doing a catch-all except: and then examining the type of my
> exception, and making a decision based on that.  It's kinda clunky.

   try:
       import module2
       module2.raise_foo_exception()
   except module2.FooException, e:
       print "Got it!"
   except:
       xi = sys.exc_info()
       print "Didn't get it.  Got this instead:", xi[0], xi[1]

-- 
Cliff Wells, Software Engineer
Logiplex Corporation (www.logiplex.net)
(503) 978-6726 x308  (800) 735-0555 x308