how to determine an 'open' string?

[holger krekel]

Sean 'Shaleh' Perry wrote:
> 
> >> 
> >> Seems a really simple solution is count the number of each type of quote in
> >> the
> >> string.  But first you need to find all of the triple quotes.
> > 
> > i thought along those lines, too, but couldn't get it correct easily. 
> > 
> >> for each quote type:
> >>   count = find all triple quotes
> >>   if count is even: closed
> > 
> > for
> >     """''' askldjl'''
> > 
> > this returns 'closed': wrong!
> > 
> 
> right, you need to handle ", then '.
> 
> import re
> 
> test_string = '"""\'\'\' askldjl\'\'\''
> 
> STATE_OPEN = 0
> STATE_CLOSED = 1
> state = STATE_OPEN
> 
> dblqt_triple = re.compile(r'(""")')
> snglqt_triple = re.compile(r"(''')")
> 
> m = dblqt_triple.search(test_string)
> count = len(m.groups())
> if count == 0 or (count % 2) == 0:
>   state = STATE_CLOSED
> new_string = dblqt_triple.sub('', test_string)
> 
> m = snglqt_triple.search(new_string)
> count = len(m.groups())
> if count == 0 or (count % 2) == 0:
>   state = STATE_CLOSED
> new_string = snglqt_triple.sub('', new_string)

what about

    '''"""'''argh"""'''"""

:-)

    holger